Sunday, August 14, 2011

What m of barium chloride is needed to react completely with 37.6 grams of sodium phosphate?

The balanced equation is 3BaCl2 + 2Na3PO4 --> 6NaCl + Ba3(PO4)2. I really need some help, thanks in advance!
Posted by Clemencia Zecchini at 12:48 PM

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